ГДЗ Математика 4 клас А. Заїка, С. Тарнавська (2021) - Частина 2 |
← Повернутися до розділів |
Назад до 534 | 535 | Вперед до 536 |
Розв'язок:
Завдання 535.
40 000 – 33 600 : 800 + 42
(249 ∙ 345 – 1905) : 300 + 220
9400 : 200 ∙ 15 – 350
(507 ∙ 39 + 7427) : 400 – 68
2 1 3
40000 – 33600 : 800 + 42 = 40000
1)
- | 3 | 3 | 6 | 0 | 0 | 8 | 0 | 0 |
3 | 2 | 0 | 0 | 4 | 2 | |||
- | 1 | 6 | 0 | 0 | ||||
1 | 6 | 0 | 0 | |||||
0 |
2)
- | 4 | 0 | 0 | 0 | 0 |
4 | 2 | ||||
3 | 9 | 9 | 5 | 8 |
3)
+ | 3 | 9 | 9 | 5 | 8 |
4 | 2 | ||||
4 | 0 | 0 | 0 | 0 |
1 2 3
9400 : 200 • 15 – 350 = 355
1)
- | 9 | 4 | 0 | 0 | 2 | 0 | 0 |
8 | 0 | 0 | 4 | 7 | |||
- | 1 | 4 | 0 | 0 | |||
1 | 4 | 0 | 0 | ||||
0 |
2)
× | 4 | 7 |
1 | 5 | |
2 | 3 | 5 |
4 | 7 | |
7 | 0 | 5 |
3)
- | 7 | 0 | 5 |
3 | 5 | 0 | |
3 | 5 | 5 |
1 2 3 4
(248 • 345 – 1905) : 300 + 220 = 500
1)
× | 2 | 4 | 9 | |
3 | 4 | 5 | ||
1 | 2 | 4 | 5 | |
9 | 9 | 6 | ||
7 | 4 | 7 | ||
8 | 5 | 9 | 0 | 5 |
2)
- | 8 | 5 | 9 | 0 | 5 |
1 | 9 | 0 | 5 | ||
8 | 4 | 0 | 0 | 0 |
3)
- | 8 | 4 | 0 | 0 | 0 | 3 | 0 | 0 |
6 | 0 | 0 | 2 | 8 | 0 | |||
- | 2 | 4 | 0 | 0 | ||||
2 | 4 | 0 | 0 | |||||
0 |
4)
+ | 2 | 8 | 0 |
2 | 2 | 0 | |
5 | 0 | 0 |
1 2 3 4
(507 • 39 + 7427) : 400 – 68 = 0
1)
× | 5 | 0 | 7 | |
3 | 9 | |||
4 | 5 | 6 | 3 | |
1 | 5 | 2 | 1 | |
1 | 9 | 7 | 7 | 3 |
2)
+ | 1 | 9 | 7 | 7 | 3 |
7 | 4 | 2 | 7 | ||
2 | 7 | 2 | 0 | 0 |
3)
- | 2 | 7 | 2 | 0 | 0 | 4 | 0 | 0 |
2 | 4 | 0 | 0 | 6 | 8 | |||
- | 3 | 2 | 0 | 0 | ||||
3 | 2 | 0 | 0 | |||||
0 |
4) 68 – 68 = 0