ГДЗ Математика 4 клас А. Заїка, С. Тарнавська (2021) - Частина 2 |
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| Назад до 638 | 639 | Вперед до 640 |
Розв'язок:
Завдання 639. Виконай обчислення.
32 ∙ 340 + 78 ∙ 115
124 ∙ 180 – 86 ∙ 95
(19 616 – 16 808) : (72 ∙ 39) ∙ 19 909
212 ∙ (8209 – 7709) : (760 : 8 + 105)
1 3 2
32 • 340 + 78 • 115 = 19850
1)
| × | 3 | 2 | ||
| 3 | 4 | 0 | ||
| 1 | 2 | 8 | ||
| 9 | 6 | |||
| 1 | 0 | 8 | 8 | 0 |
2)
| × | 1 | 1 | 5 |
| 7 | 8 | ||
| 9 | 2 | 0 | |
| 8 | 0 | 5 | |
| 8 | 9 | 7 | 0 |
3)
| + | 1 | 0 | 8 | 8 | 0 |
| 8 | 9 | 7 | 0 | ||
| 1 | 9 | 8 | 5 | 0 |
1 3 2
124 • 180 – 86 • 95 = 14150
1)
| × | 1 | 2 | 4 | |
| 1 | 8 | 0 | ||
| 9 | 9 | 2 | ||
| 1 | 2 | 4 | ||
| 2 | 2 | 3 | 2 | 0 |
2)
| × | 8 | 6 | |
| 9 | 5 | ||
| 4 | 3 | 0 | |
| 7 | 7 | 4 | |
| 8 | 1 | 7 | 0 |
3)
| - | 2 | 2 | 3 | 2 | 0 |
| 8 | 1 | 7 | 0 | ||
| 1 | 4 | 1 | 5 | 0 |
1 3 2 4
(19616 – 16808) : (72 • 39) • 19909 = 19909
1)
| - | 1 | 9 | 6 | 1 | 6 |
| 1 | 6 | 8 | 0 | 8 | |
| 2 | 8 | 0 | 8 |
2)
| × | 7 | 2 | |
| 3 | 9 | ||
| 6 | 4 | 8 | |
| 2 | 1 | 6 | |
| 2 | 8 | 0 | 8 |
3) 2808 : 2808 = 1
4) 1 • 19909 = 19909
4 1 5 2 3
212 • (8209 – 7709) : (760 : 8 + 105) = 530
1)
| - | 8 | 2 | 0 | 9 |
| 7 | 7 | 0 | 9 | |
| 5 | 0 | 0 |
2)
| - | 7 | 6 | 0 | 8 | |
| 7 | 2 | 9 | 5 | ||
| - | 4 | 0 | |||
| 4 | 0 | ||||
| 0 |
3) 95 + 105 = 200
4)
| × | 2 | 1 | 2 | ||
| 5 | 0 | 0 | |||
| 1 | 0 | 6 | 0 | 0 | 0 |
5)
| - | 1 | 0 | 6 | 0 | 0 | 0 | 2 | 0 | 0 |
| 1 | 0 | 0 | 0 | 5 | 3 | 0 | |||
| - | 6 | 0 | 0 | ||||||
| 6 | 0 | 0 | |||||||
| 0 |